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Nov 27, 2024
11:58
:23
am
royal_blue
All-American
We need at least 1 loss from ISU/ASU AND we need to win vs HOU. So:
P(at least one ISU/ASU loss) = 1 - P(Both ISU/ASU win) = 1 - (.715 * .515) = .632
P(we win vs HOU) = .872
P(we go to CCG) = .872 * .632 = .551
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royal_blue
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royal_blue
Joined
Nov 27, 2006
Last login
Nov 27, 2024
Total posts
2,931 (5 FO)
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Messages
Author
Time
28.5 + 48.5 X 87.2 = 67% (BYU goes to Arlington)
Plantagenet
11:38am
<< Deleted >>
bluecougar1985
11:40am
I get a 36.8% chance based on those odds that both don’t win. Times that by
bluecougar1985
11:42am
There's a 28.5% + 48.5% chance one of them loses.
Plantagenet
11:45am
You don't add them. What if both were 90% does that equal a 180%
cougarfann888
11:47am
So, I'll throw my hat in: it's 55.2%
Cosmo's Uncle
11:46am
Yep, you are right. Mine did seem off as well.
bluecougar1985
11:48am
Dang mathematicians!
Plantagenet
11:53am
Yes.
jollaksentie
12:03pm
<< Deleted >>
LeftOfNormal
11:46am
But only an 85% chance of that happening.
DudeBro
11:47am
RE: 28.5 + 48.5 X 87.2 = 67% (BYU goes to Arlington)
cougarfann888
11:54am
We need at least 1 loss from ISU/ASU AND we need to win vs HOU. So:
royal_blue
11:58am
This is correct.
jollaksentie
12:01pm
Plus maybe another .001 or so that the scenario where we don't have to win happe
goidcougs
12:35pm
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